Transformation Of Graph Dse Exercise 🔥 Bonus Inside

Thus stationary points at ( x=0, 2 ). Trig graphs test horizontal scaling (period change) and vertical scaling (amplitude) most intensely.

A and D are equivalent and correct. Reflection first: ( y = -\sin x ), then +2. Exercise Set 2: Finding the Original Graph (Reverse Transformation) DSE often asks: Given the image graph, find the pre-image function. transformation of graph dse exercise

Stationary points occur when ( g'(x)=0 ). ( g(x) = 2f(1-x) + 1 ) ( g'(x) = 2 \cdot f'(1-x) \cdot (-1) = -2 f'(1-x) ) Set ( g'(x)=0 \implies f'(1-x)=0 ). Thus stationary points at ( x=0, 2 )

The graph of ( y = f(x) ) is translated 3 units right and then reflected in the y-axis to become ( y = \sqrt4 - x^2 ). Find ( f(x) ). Reflection first: ( y = -\sin x ), then +2

Start with ( y = x^2 - 4 ) (vertex at (0,-4), roots at ±2). Step 2: Apply modulus: ( y = |x^2 - 4| ) – reflect negative part above x-axis. Step 3: Subtract 1: shift graph down by 1.