Jawapan Buku Teks Fizik Tingkatan 4 Kssm Aktiviti 13 Top Full Today

| Angle of incidence, i (°) | Angle of refraction, r (°) | sin i | sin r | n = sin i / sin r | |---------------------------|----------------------------|-------|-------|-------------------| | 20 | 13 | 0.342 | 0.225 | 1.52 | | 30 | 19 | 0.500 | 0.326 | 1.53 | | 40 | 25 | 0.643 | 0.423 | 1.52 | | 50 | 31 | 0.766 | 0.515 | 1.49 |

A light ray travels from water (n = 1.33) into air. The angle of incidence in water is 35°. Calculate the angle of refraction in air.

Diamond has a high refractive index (2.42) and a low critical angle (24.4°). Light entering diamond undergoes multiple total internal reflections before exiting, creating a sparkling effect. Glass has a lower refractive index (~1.5) and higher critical angle, so less total internal reflection occurs. Section D: Lenses (Aktiviti 13.4) Question: A convex lens has a focal length of 10 cm. An object of height 2 cm is placed 15 cm from the lens. Find: a) Image distance b) Magnification c) Image height | Angle of incidence, i (°) | Angle

Magnification, m = v/u = 30/15 =

Why does a diamond sparkle more than a glass piece? Diamond has a high refractive index (2

n = speed of light in vacuum / speed of light in medium n = (3.0 × 10⁸) / (2.0 × 10⁸) = 1.5

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Using Snell’s Law: n₁ sin i = n₂ sin r 1.33 × sin 35° = 1.00 × sin r 1.33 × 0.574 = sin r sin r = 0.763 r = sin⁻¹ (0.763) = 49.8° Section C: Total Internal Reflection (Aktiviti 13.3) Question: The critical angle for diamond is 24.4°. Calculate the refractive index of diamond.